Binary Representation for Digital Distortion

[Big Pete]

Digital audio is made up of 1 an 0's .
For you guys with a bit of a deep background in this you will know that we have the Most Signifigant Bit and the Least Signifigant Bit with some 1 and 0's in between to represent the audio , how is digital distortion represented in this case .

[Robotnik]

22222222
That's 8-bit digital distortion. [img]images/icons/grin.gif[/img]

It's not that the digital word is represented in a different way, it's that digital audio has a maximum amplitude of, for example, 11111111, in an 8-bit system regardless of the input gain. When the input (or output) signal is greater then the amplitude of the digital system, rounding down to the maximum amplitude occurs. This causes a square-shaped waveform which we hear as digital "distortion."

[where02190]

I think it goes like this...
0100010100UCH!!!!!!!!01010001110101011OUCH ST0P THAT!!!!0100101111101....

[Kev]

- and when in Rome.
III..IV..II..IVX .... VIII bit. or is that IIX bit??... should have paid attention in school.
[img]images/icons/wink.gif[/img]

[guessi]

to me it seems that you have to define how many maximum-samples in a row are "OVERLOAD". according to bob kaatz (www.digido.com) it should be 3 samples on after another. but some times it is 6 samples or whatever.

when ther is a signal with more than 3 maximum samples it surely is some kind of squarewave. and that means distortion and overload.

but of course I really appreciated my 2 forespeaker's explanations!

[Big Pete]

Thanks alot guys, your answers helped me out with my problem , I THINK !!!!!. [img]images/icons/smile.gif[/img]